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Thursday, November 2, 2017

Proton Radius Puzzle - Solved



The proton radius puzzle has been around since 2010 and repeatedly shown by experiment that the proton radius is actually about -4% smaller than the official CODATA measured value for the proton radius.

Solution:
The proton is a vortex in the yet to be defined super fluid aether

Proton Parameters of interest:
mass - energy and mass ratios (such as proton to electron mass ratio and others)
radius
charge
magnetic momentum
angular momentum


From standard quantized angular momentum or quantization of circulation of a super fluid, the mass-radius relationship of the proton can be derived:

$m_pr_p={2h\over\pi c}$

And, using this mass-radius relationship and analyzing the proton as a rotating surface charge of elementary charge evenly distributed over the surface of the proton, the proton's magnetic moment can be derived (see derivation):
$\mu_p={8\over3}\mu_N$
$\mu_p=2.666\mu_N$  ;($\mu_p=2.657\mu_N$, possible relativistic correction)
$\mu_N={e\hbar\over2m_p}$
$\mu_p={er_pc\over3}$  ; possible "minor (-0.4%)" relativistic correction: $\mu_p={er_pc\sqrt{1-\alpha}\over3}$
$e=$ elementary charge
$\hbar={h\over2\pi}=$ reduced Planck's constant
$h=$ Planck's constant
$c=$ speed of light

Using this value of the proton's magnetic moment, the peak resonance frequency (Larmor frequency) of 1H (free proton, rest proton, 0K) can be calculated to be: 40.6538308 MHz /Tesla (40.55MHz/Tesla relativistic correction). <~~ note this is different than the mainstream's 42.58MHz/Tesla (mainstream is designed to be off-peak for NMR/MRI).  While this claim may be alarming to some, realize that there is a linear relationship between angular momentum and radius, and likewise, magnetic (angular) momentum.  Therefore, since the proton radius is 4% smaller, the proton's magnetic moment is also 4% smaller.


Using mks units...
This is the proton, rest state, condensed-matter type analysis.  These are the fundamental properties of the proton.

Much more is implied by this as Haramein and others has been saying for a long time.

Addendum:
${m_p\over m_e}={r_e\over r_p}={\alpha^2\over\pi r_pR_{\infty}}=1836.15267$
Where:
$m_pr_p={2h\over\pi c}=4\ell m_{\ell}$
$r_p=0.841235640294664\;fm$
$m_p=$ proton mass
$m_e=$ electron mass
$r_p=$ proton radius
$r_e=$ effective torque arm radius for electron
$\alpha=$ fine-structure constant
$h=$ Planck constant
$c=$ speed of light
$R_{\infty}=$ Rydberg constant
$\ell=$ Planck length
$m_{\ell}=$ Planck mass

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