Sunday, August 6, 2017

Proton Charge to Mass Ratio



$${e\over m_p}=\sqrt{\pi^2{r_p}^2c^3\alpha\epsilon_0\over{2h}}$$
$e=$ elementary electron charge
$m_p=$ proton mass
$r_p=$ proton radius
$c=$ speed of light
$\alpha=$ fine-structure constant
$\epsilon_0=$ permittivity of vacuum
$h=$ Planck's constant
$${e\over m_p}={\pi r_pcq\over{2h}}$$
$e=q=$ elementary charge


Link for Google Calculation of charge to mass ratio of proton

elementary charge / proton mass =
95 788 332.2 s A / kg
(elementary charge)/m_p=


Proton Charge-to-Mass Ratio
First! (?)
The Surfer, OM-IV

The Proton: Superfluid Vortex Quantization


Vortex-quantization in a superfluid, circulation is quantized:
$$\oint_C\mathbf{v}\cdot d\mathbf{l}={2\pi\hbar\over m}n$$
$\mathbf{v}=$ velocity
$\mathbf{l}=$ path length, $d\mathbf{l}=rd\theta$, for dot product
$\hbar={h\over{2\pi}}$ = Reduced Planck's constant, and $h$, Planck's constant
$m=$ mass
$n=$ integer, quantized

for uniform circular motion, constant velocity:
$\oint_Cd\mathbf{l}={\int_0}^{2\pi}rd\theta=2\pi r$, circumference of circle
$$\oint_C\mathbf{v}\cdot d\mathbf{l}={\mathbf{v}2\pi r}$$
$${\mathbf{v}2\pi r}={2\pi\hbar\over m}n$$
$${m r}={2\pi\hbar\over {\mathbf{v}2\pi}}n$$
$${m r}={\hbar\over {\mathbf{v}}}n$$
$${m r}={nh\over {2\pi\mathbf{v}}}$$
For a proton that is a vibration in the superfluid vacuum aether, the phase velocity of circulation is the speed of light, $c$:
 $$\therefore{m r}={nh\over {2\pi c}}$$
the proton being the $n=4$ case:
 $$\therefore{m r}={2h\over {\pi c}}$$
which is the same equation derived for the proton using the quantized angular momentum approach and Haramein's team's geometrical information theory holofractographic approach.

This is implying that the vacuum is a superfluid.

Still need to derive why the proton mass is what it is... and why the proton is the $n=4$ case.

The Surfer, OM-IV

Wednesday, August 2, 2017

XY = c , Mathematical Solutions


Math:
$XY=c$
Let $X=m(r)$
Let $Y=r(m)$
$c=constant$
m(r) is a function of r, $m={c\over r}$
r(m) is a function of m, $r={c\over m}$

What can mathematically be said about all the solutions to this type of equation? A product of two variables is a constant?

Time for math.

#Math

more later about this brief post,
- mr

Some related work here:
http://www.stumblingrobot.com/2016/02/22/find-the-orthogonal-trajectories-of-the-family-xy-c/


And, example #2 here:
https://proofwiki.org/wiki/Orthogonal_Trajectories/Rectangular_Hyperbolas
&

Quantized levels might look something like this, however, it must be reviewed:

The Surfer, OM-IV