## Friday, July 28, 2017

### How Does the Mass Radius Product, MR, Become Specific Unique Mass and Radius Values?

(this post requires some rethinking)  7/29/17  -mr
It seems this still does not explain why the mass of the proton is what it is... back to drawing board!﻿
$$mr={2h\over \pi c}$$

How does the mass become a specific value and the radius for a specific object or "particle", such as the proton?  In other words, why can't or why doesn't the mass come out twice as much and the radius half as much? Or, why can't the proton mass be 4% smaller, and the radius 4% bigger? It still works in the equation... (approximately.  Linearization errors...)

This is because the solution is a cymatics-like resonance in the vacuum, and the mass ratio, $\phi$, is actually an information-theory area ratio  divided by a geometric volumetric ratio: (Haramein's team's work):

$$\phi={\eta\over R}$$
$$\eta={Area_{objectSurface}\over A_{equitorialXsectionPSU}}$$
$$R={Volume_{object}\over Volume_{PSU}}$$
(the PSU is the Planck Sphereical Unit, a sphere of diameter Planck length, ${\ell}_{\ell}$)
for the proton, a factor of 2 is needed:

$$m_p={2{\eta\over R}m_{\ell}}$$
$m_p=$ Proton mass
$m_{\ell}=$ Planck mass

When the terms for eta over R, the mass ratio, are expanded, the results is:
$$m_pr_p={2h\over \pi c}$$
$r_p$ is Proton radius.
$h=$ Planck's constant
$c=$ Speed of Light
$\pi$ is good.

So what you have is a 2D area ratio term & a 3D volumetric ratio which resonates similar to cymatics-type oscillations in a substrate material, the substrate being the new superfluid like aether of the vacuum.

It's pretty simple math and this approach gives the same answer as the quantized angular momentum approach.  Thus, the higher-level 3D approach seems to be more inclusive, as it can be used to calculated the mass of black holes, protons, and electrons.  What's next?

The details of the math and derivation have been outlined previously: