This is preliminary, however, it is important to show since new concepts are needed as Haramein has been saying for a long time. It's a little video of a model of the proton spinning and the line is like the electron arc, even though it is much faster and the length of the arc is:

$$R_e={4LM \over M_e}={4Lm_{\ell}\over m_e}={{4L\alpha^2\over 4\pi\ell R_{\infty}}}=$$

$${{\alpha^2\over \pi R_{\infty}}}=1.54463707 \times 10^{-12}meters=1.54463707\;pm$$

$L=\ell=Planck\;Length$

$M=m_\ell=Planck\;mass$

$M_e=Mass\;of\;electron$

$R_{\infty}=R_H=Rydberg\;constant$ (simply dealing with mono-protonic things at this time)

$\alpha=fine-structure\;constant$

(fine-structure+constant)^2/pi/(rydberg+constant)=

$${{\alpha^2\over \pi R_{\infty}}}=1.54463707 \times 10^{-12}meters=1.54463707\;pm$$

$L=\ell=Planck\;Length$

$M=m_\ell=Planck\;mass$

$M_e=Mass\;of\;electron$

$R_{\infty}=R_H=Rydberg\;constant$ (simply dealing with mono-protonic things at this time)

$\alpha=fine-structure\;constant$

(fine-structure+constant)^2/pi/(rydberg+constant)=

©2015 Mark Eric Rohrbaugh ©2015 Lyz Starwalker

See the Cross (Maltese Cross) starting to show up?

This is pure gold, Jerry, Prue gold.

Kramer, you're really out there.

Kramer: "I'm already gone, Jerry."

Again, this is preliminary and much more work is needed to check multi-nuecleon atoms, etc.

For something similar:

Soon we will be able to handle this and much much more...