Monday, August 3, 2015
Sunday, August 2, 2015
Ancient Egyptian Duck - The Resonance Academy #4 / Project Rubber Ducky Mascott
Ancient Egyptian Duck
Unraveling every riddle, Egyptian Duck is at the top of the heap, or he should be. Please help Egyptian Duck to the top of popular post page for a special post!
The Surfer, OM-IV
Golden Ratio ($\varphi$) Fractally embedded in Nature - Platonic Solids
From wikipedia page on Platonic solid:
Cartesian coordinates[edit]
For Platonic solids centered at the origin, simple Cartesian coordinates are given below. The Greek letter Ο is used to represent the golden ratio
.
.| Figure | Tetrahedron | Octahedron | Cube | Icosahedron | Dodecahedron | |||
|---|---|---|---|---|---|---|---|---|
| Vertices | 4 | 6 (2×3) | 8 | 12 (4×3) | 20 (8+4×3) | |||
| Orientation set | 1 | 2 | 1 | 2 | 1 | 2 | ||
| Coordinates | (1,1,1) (1,−1,−1) (−1,1,−1) (−1,−1,1) | (-1,-1,-1) (-1,1,1) (1,-1,1) (1,1,-1) | (±1, 0, 0) (0, ±1, 0) (0, 0, ±1) | (±1, ±1, ±1) | (0, ±1, ±Ο) (±1, ±Ο, 0) (±Ο, 0, ±1) | (0, ±Ο, ±1) (±Ο, ±1, 0) (±1, 0, ±Ο) | (±1, ±1, ±1) (0, ±1/Ο, ±Ο) (±1/Ο, ±Ο, 0) (±Ο, 0, ±1/Ο) | (±1, ±1, ±1) (0, ±Ο, ±1/Ο) (±Ο, ±1/Ο, 0) (±1/Ο, 0, ±Ο) |
| Image | ||||||||
., is all over the Platonic solids.
Considering that $\varphi$, the Golden ratio has been shown by many to be fractally embedded in all of Nature, Dan Winter's work is significanlty taking off where the ancients left off and giving meaning to:
...and more.
https://en.wikipedia.org/wiki/Toroidal_polyhedron <-- interesting as well!
https://en.wikipedia.org/wiki/Spherical_polyhedron
WHERE IS PEZ THE DUCK? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~>>>>>>>>>>>>>
Search for PEZ in this blog and bring him up the chain of posts to meet Bozon T. and his other Duck Family members!!!
https://en.wikipedia.org/wiki/Toroidal_polyhedron <-- interesting as well!
https://en.wikipedia.org/wiki/Spherical_polyhedron
WHERE IS PEZ THE DUCK? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~>>>>>>>>>>>>>
Search for PEZ in this blog and bring him up the chain of posts to meet Bozon T. and his other Duck Family members!!!
PEZ
Saturday, August 1, 2015
(Ionized) Hydrogen Radii I, II, III, Using Google Calculator
Signed Jeanie bottle 2011 (signed by Barbara Eden and the late Larry Hagman)
Dan Winter's amazing breakthrough work / equation is of the form:
$$Radii\;or\;Wavelength = \ell \times \phi^n = L \times \Phi^N $$
where
$\ell = L= Planck\;Length$
$\phi = \Phi= Golden\;Ratio$
$n= N \in Integers$
Here is using the google calculator in Chrome to calculate ionized hydrogen radii I, II, III:
Radii I = $\ell \phi^{116}=$ 0.282527789Γ
Radii II = $\ell \phi^{117}=$ 0.457139566Γ
Radii III = $\ell \phi^{118}=$ 0.739667355Γ
$\ell = L = Planck\;Length = 1.61619926 \times 10^{-35}meters$
$\phi =\Phi = Golden\;Ratio = $ 1.61803398875
Google Calculator Links for Ionized Hydrogen Radii:
Where does this equation come from? From the mind of a genius, Dan Winter. Upon further analysis, since things in Nature unfold from an embedded fractal of the golden mean ratio, $\Phi$, it is clear Dan is on the right path, AND THE ONLY PATH to function coherently with and within Nature.
Here is a link to a PDF paper on the ionized hydrogen radii (I, II, and III):
http://precedings.nature.com/documents/2929/version/1
http://precedings.nature.com/documents/2929/version/1/files/npre20092929-1.pdf
http://arxiv.org/abs/0902.1184
This next comment requires further evaluation, however, it looks like Dan's equation IS the one key solution to Dirac's equation that allows for gravity, life, etc. Dirac's equation is a relativistic form of the Schrodinger wave equation. These are key quantum mechanical equations that explain information about matter on very small scales, and in some limit or another will approach macroscopic behavior. This is significant key work Dan has been doing and it will soon be linked to mainstream science, if this step has not already done so. A few more hours to review....
Friday, July 31, 2015
Phi, Psi, Fo, Fum, Bloch Man's the Man to Git 'er Done!!!
Bloch Man - Willie the Giant
Thursday, July 30, 2015
Get Ahead, Don't Be Left Behind - The Resonance Academy #3
Comet Lovejoy
$384 and yet get access to:
It's empowering and adds to one's purpose!
Click here or on Academy links on PhxMarkER blog.
(the green of the blog represents the bridge (from lower to higher self), intuition, and the Hermetic traditions)
PEZ the Duck Coming at You!
Physics and creativity:
PEZ the Duck
Feynman plays the bongos.
Might as well let Feynman monkee around and play the bongos, it's goingto take some time for PEZ the Duck to join up with his Duck Family...
The Surfer, OM-IV
Wednesday, July 29, 2015
Electron Torque Balances Proton Torque WORK #1
Haramein's equation, with no competing interest:
$$M_PR_P=4 L M$$
(one form of a few)
add to it $M_ER_E$:
$$M_PR_P=4 L M=M_ER_E$$
using The Answers.
Confused / puzzled?
It's all about torque, spin, and balance:
I'll be looking at SchrΓΆdinger's wave equation, Dirac's relativistic version, and more to analyze in detail each wave funtion, and put legs on this theory.
The Surfer, OM-IV
$$M_PR_P=4 L M$$
(one form of a few)
add to it $M_ER_E$:
$$M_PR_P=4 L M=M_ER_E$$
using The Answers.
Confused / puzzled?
It's all about torque, spin, and balance:
"back of the hand balance..."
By including the whole, looking at proton and electron at same time, progress can be made.I'll be looking at SchrΓΆdinger's wave equation, Dirac's relativistic version, and more to analyze in detail each wave funtion, and put legs on this theory.
The Surfer, OM-IV
"I have seen the eyes"
Proton-Electron Arc or Arc Length (Covenant of the Arc)
Since this is simply an extension to basic pre-existing quantum mechanics, there is no need to reformulate or revisit all of quantum mechanics - that exercise is left up to the reviewer.
This equation can be solved to get $R_E$ or we can use and earlier post get get the expression for $R_E$ I developed in 1987-1991: The Answers
$$R_E={\alpha^2\over \pi R_H}$$
Since we are dealing presently with mono-protonic situations (single proton hydrogen in a low energy, non-ionized, unperturbed state) $R_H$ is used rather than $R_{\infty}$.
What is this electron radius and why is it so huge? From the equation
$$M_PR_P=4LM=M_ER_E$$
one can see that the torque / spin of the proton is matched by the electron - for every action there is an equal and opposite reaction, and the length is such that the product of the electron radius and the electrom mass EQUALS the same 4LM (Haramein's $M_PR_P=4LM$ equation where
$M_P=Mass\;of\;Proton$
$R_P=Radius\;of\;Proton$
$L=Planck\;Length$
$M=Planck\;Mass$
$M_E=Mass\;of\;Electron$
$R_E=Radius\;of\;Electron$
.
.
.
and this balances both the electron and proton to a mass ratio of
$$\mu={\alpha^2\over {\pi r_p R_H}}=1836.15267$$
$$R_E={\alpha^2\over \pi R_H}=1.54463707 10^{-12} m = 1.54463707 pm$$
$$Radius\;of\;Proton={4LM \over M_P}=0.841235641fm$$
The mass of the electron is
$$M_E={M_PR_P\pi R_H\over \alpha^2}$$
Arc length, when dealing with radians, is simply the product of the radius and the angle subtended. Since we are doing the electron for 180 degrees, or $\pi$ radians: $S=\pi Radius$
$$S_{E1}={\alpha^2 \over R_H}=4.85262048pm$$
For comparison, if we made an arc length using the proton radius:
$$S_{proton radius - arc}=R_P \pi= {4Lsqrt(hbar*c/G)*\pi \over M_P}=2.64281971fm$$
theses values are way shorter than the latest plasmon wavelength observed in single-wall nanotubes.
More later on interpreting this.
The Surfer, OM-IV
Subscribe to:
Posts (Atom)







