Saturday, June 24, 2023

n=1 (DRAFT): A Physics Letter A (Mathematical Physics): Proton Radius, the Rydberg Equation, and Fundamental Physics Constants

Proton Radius, the Rydberg Equation, and Fundamental Physics Constants






n=1 Bohr_model


Highlights

  • Complete solution to proton radius puzzle
  • Correction to Rydberg Equation (extends with proton to electron mass ratio)
  • Roots of Full Rydberg Equation define fundamental physics constants

Abstract

A mathematical solution for the proton radius has been derived which adds a term to the Rydberg equation.  By avoiding using the reduced mass approximation (as has been done in solid-state theory and the hydrogen atom's analytical solution to the Schrödinger Wave Equation) and including the proton to electron mass ratio which brings in the proton radius.  A proton to electron mass ratio of 1836.15267 is calculated with a proton radius of 0.8412fm.

Keywords

Proton radius; proton to electron mass ratio; Rydberg equation 


1.0 Introduction
This derivation makes use of, as a starting point,: $$R_M={R_\infty\over {1+{m_e\over M}}}[1]$$

1.1 Governing model
Schrödinger Equation (and Full Wave Equation)
(At lowest energies, n=1, Bohr model and Schrödinger model are equivalent for 1H hydrogen)

2.0 Derivation:
$R_M={R_\infty\over {1+{m_e\over M}}}$
$R_M(1+{m_e\over M})=R_\infty$
$(1+{m_e\over M})={R_\infty\over R_M}$
$1={R_\infty\over R_M}-{m_e\over M}$
For hydrogen, 1H @ 0°K:, $M=m_p$
$1={R_\infty\over R_H}-{m_e\over m_p}$

For the electron to proton mass ratio (inverse of proton to electron mass ratio), the derivation of the proton to electron mass ratio:
$$\mu={m_p\over m_e}=1836.15267\dots$$
$$m_e={2R_{H}h\over c\alpha^2}$$
( $m_e$ for the electron mass: Derivation of Rydberg equation for electron mass, also see [1] above)
$$m_e{\alpha^2\over R_{H}}={2h\over c}$$
$$m_e{\alpha^2\over \pi R_{H}}={2h\over \pi c}$$
By substitution, let $r_e={\alpha^2\over\pi R_{H}}$, then:
$$m_er_e={2h\over\pi c}$$
Now, because for every action there is an equal and opposite reaction, for every force there is an equal and opposite force, for every torque, there is an equal and opposite torque, equate $m_pr_p$ to $m_er_e$ to balance torque/spin between proton and electron:
$$m_er_e={2h\over\pi c}=m_pr_p$$
$$\therefore {m_p\over m_e}={r_e\over r_p}={\alpha^2\over\pi r_pR_{H}}=1836.15267$$
Where:
$$m_pr_p={2h\over\pi c}=4\ell m_{\ell}$$
$$r_p=0.841235640(294664)\;fm$$(Google Calculator for r_p)

$\mu={m_p\over m_e}={\alpha^2\over\pi r_pR_H}=1836.15267$ (Google Calculator for μ)
$1={R_\infty\over R_H}-{\pi r_pR_H\over \alpha^2}$
$R_\infty={m_ee^4\over 8{\epsilon_0}^2h^3c}$
$$1={{m_ee^4\over 8{\epsilon_0}^2h^3cR_H}}-{\pi r_pR_H\over \alpha^2}\;[2]$$

$R_{H}=$ Rydberg constant for 1H hydrogen atom
$R_{\infty}=$ Rydberg constant for massive nucleus atom
$R_{M}=$ Rydberg constant for Multi-proton atom
$m_{\ell}=$ Planck mass

3. Other Solutions for proton mass (ratio)
Boundary Value Problem method of determining coefficients use with wave equation for both electron and proton; Geometrical assuming vacuum density and information theory of black hole event horizon - Haramein et al

4. Conclusions
This derivation provides a polynomial [2] that predicts future trends of fundamental physics constants coefficient values as the measurements are refined over the years to be more precise.  The polynomial [2] may also actually DEFINE the constants - ongoing work with the polynomial investigating stability and convergence continues.  

There are various algorithms one can envision setting some constants as known and iterating to find the others, and likely all constants in the equation.  A timebase reference is also needed and likely why c is defined in mainstream via decree rather than derivation. 

Credit authorship contribution statement
Mark's derivation with Lyz's input to equate/balance the proton and electron 

Declaration of Competing Interest
n/a

Data availability
n/a

References
[standard]

*Mµ - Master of the µniverse, Macro and micro, inner and outer-dimensional


The Surfer, OM-IV
©2023 Mark Eric Rohrbaugh & Lyz Starwalker ©2023

Friday, June 9, 2023

The Physics Constants as a Boundary Value Problem

A glaring incompleteness of current scientific theory is the complete and total lack of solving the constants as a boundary value problem.
https://en.wikipedia.org/wiki/Boundary_value_problem

There is a large body of literature on this subject and electrical engineers known it well.  Signals and System engineering requires it. 
The constants are coefficients of a boundary value problem. 

Boundary Conditions:
  1. Single Hydrogen atom - full analytical solution to Schrödinger's Equation [1]
  2. 0ºK - Absolute Zero, no phonons/vibrations
  3. No applied EM fields
  4. vacuum? (implied by 1.)
  5. t = -, 0, +∞, t + 2πft
  6. Extract the https://en.wikipedia.org/wiki/Characteristic_polynomial
  7. Instrinsic/characteristic polynomial/solution?
  8. 2 body problem, do not reduce to single body such as in Squalid-State
  9. n=1, ?more?
Considering it is simply a second order wave equation, what is the reason mainstream science has ignored the fundamentals?
This is quite different than looking at the physics constants as "free" parameters.



http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/hydsch.html*
* DO NOT USE REDUCED MASS ASSUMPTION!
[1] - establishes 1H@0ºK as reference mass - the Hydrogen atom / proton is a reference for all other mass

https://en.wikipedia.org/wiki/Nearly_free_electron_model <~~ Works for Technology not Science!
The Surfer, OM-IV