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| credit |
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| from: https://forums.autodesk.com/t5/inventor-forum/3d-array-of-spheres/td-p/8054413 |
The spacing of the protons, center to center, is $2r_p$. For a standing wave phononic vibration in the crystal, proton to proton spacing is $1\over2$ wavelength, so the shortest standing wave wavelength is $4r_p$, thus the $\pi\over2$? in:
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| https://phxmarker.blogspot.com/2021/05/speed-limit-of-sound-fine-structure.html |
$$f_u={v_u\over\lambda_u}$$
$$v_u=c\sqrt{{\pi\over2}r_pR_H}$$
$$\lambda_u=4r_p$$
$$f_u=c\sqrt{{\pi\over32}{R_H\over r_p}}$$
Wavelength of the sound is $4r_p=3.3656 femtometers$
A subharmonic of a factor 178,274,305 would bring the frequency down to the middle the visible spectrum:
Vibrating a crystal of metallic hydrogen at 60GHz would make it radiate in the visible spectrum?
(need to revisit basics - Work In Progress -WIP)
(I would imagine there is a lot of noise in space)
Modifications for Tension-Pressure and density:
$$f_u={v_u\over\lambda_u}\sqrt{T\over\mu}$$
$$v_u=c\sqrt{{\pi\over2}r_pR_H}$$
$$\lambda_u=4r_p$$
$$f_u=c\sqrt{{\pi\over32}{R_H\over r_p}}\sqrt{T\over\mu}$$
Might have to review crystal resonators to progress:
Once the equation is corrected for Pressure/density/elasticity/temperature or whatever, perhaps Jupiter's 22.3MHz emmissions can be simply explained.
Moar coming.
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| source |
Some effect like this, however, with the protons+ moving via phonon standing wave in a periodic 3D metallic crystal, for when the phonon frequency equals the photon frequency, however, even that assumption may be wrong... (this is LIVE derived crash and burn, results will verify over time):
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| https://en.wikipedia.org/wiki/Bremsstrahlung |
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| https://radiojove.gsfc.nasa.gov/library/sci_briefs/discovery.html |
