Multiply both sides by $R_H$ to clearly see the 2nd order polynomial in $R_H$ |
$$R_H={{m_ee^4}\over{8\epsilon_0^2h^3c}} - {\pi r_pR_H^2\over{\alpha^2}}$$
$${\pi r_p\over{\alpha^2}}R_H^2+R_H-{{m_ee^4}\over{8\epsilon_0^2h^3c}} = 0$$
This can be used to bridge / map previous $R_H$ to a new $R_H$ that includes the electron to proton mass ratio term that was dropped during the Solid State derivation of the Quantum Theory to show what the correction terms are to the original $R_H$.
Moar later.
One could argue that THIS is the correct solution for R_H and spawn a whole re-look at previous work.
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