Metallic mean

Gold, silver, and bronze ratios within their respective rectangles.

The metallic mean (also metallic ratio, metallic constant, or noble mean^[1]) of a natural number $n$ is a positive real number, denoted here $S_{n},$ that satisfies the following equivalent characterizations:

the unique positive real number $x$ such that ${\textstyle x=n+{\frac {1}{x}}}$
the positive root of the quadratic equation $x^{2}-nx-1=0$
the number ${\textstyle {\frac {n+{\sqrt {n^{2}+4}}}{2}}={\frac {2}{{\sqrt {n^{2}+4}}-n}}}$
the number whose expression as a continued fraction is
$[n;n,n,n,n,\dots ]=n+{\cfrac {1}{n+{\cfrac {1}{n+{\cfrac {1}{n+{\cfrac {1}{n+\ddots \,}}}}}}}}$

Metallic means are (successive) derivations of the golden ( $n=1$ ) and silver ratios ( $n=2$ ), and share some of their interesting properties. The term "bronze ratio" ( $n=3$ ) (Cf. Golden Age and Olympic Medals) and even metals such as copper ( $n=4$ ) and nickel ( $n=5$ ) are occasionally found in the literature.^[2]^[3]^[a]

In terms of algebraic number theory, the metallic means are exactly the real quadratic integers that are greater than $1$ and have $-1$ as their norm.

The defining equation $x^{2}-nx-1=0$ of the $n$ th metallic mean is the characteristic equation of a linear recurrence relation of the form $x_{k}=nx_{k-1}+x_{k-2}.$ It follows that, given such a recurrence the solution can be expressed as

x_{k}=aS_{n}^{k}+b\left({\frac {-1}{S_{n}}}\right)^{k},

where $S_{n}$ is the $n$ th metallic mean, and $a$ and $b$ are constants depending only on $x_{0}$ and $x_{1}.$ Since the inverse of a metallic mean is less than $1$ , this formula implies that the quotient of two consecutive elements of such a sequence tends to the metallic mean, when $k$ tends to the infinity.

For example, if $n=1,$ $S_{n}$ is the golden ratio. If $x_{0}=0$ and $x_{1}=1,$ the sequence is the Fibonacci sequence, and the above formula is Binet's formula. If $n=1,x_{0}=2,x_{1}=1$ one has the Lucas numbers. If $n=2,$ the metallic mean is called the silver ratio, and the elements of the sequence starting with $x_{0}=0$ and $x_{1}=1$ are called the Pell numbers.

Geometry

Golden ratio within the pentagram (φ = red/ green = green/blue = blue/purple) and silver ratio within the octagon.

The defining equation ${\textstyle x=n+{\frac {1}{x}}}$ of the $n$ th metallic mean induces the following geometrical interpretation.

Consider a rectangle such that the ratio of its length $L$ to its width $W$ is the $n$ th metallic ratio. If one remove from this rectangle $n$ squares of side length $W$ , one gets a rectangle similar to the original rectangle; that is, a rectangle with the same ratio of the length to the width (see figures).

Some metallic means appear as segments in the figure formed by a regular polygon and its diagonals. This is in particular the case for the golden ratio and the pentagon, and for the silver ratio and the octagon; see figures.

Powers

Denoting by $S_{m}$ the metallic mean of m one has

S_{m}^{n}=K_{n}S_{m}+K_{n-1},

where the numbers $K_{n}$ are defined recursively by the initial conditions $K 0 = 0$ and $K 1 = 1$ , and the recurrence relation

K_{n}=mK_{n-1}+K_{n-2}.

Proof: The equality is immediately true for $n=1.$ The recurrence relation implies $K_{2}=m,$ which makes the equality true for $k=2.$ Supposing the equality true up to $n-1,$ one has

{\begin{aligned}S_{m}^{n}&=mS_{m}^{n-1}+S_{m}^{n-2}&&{\text{(defining equation)}}\\&=m(K_{n-1}S_{n}+K_{n-2})+(K_{n-2}S_{m}+K_{n-3})&&{\text{(recurrence hypothesis)}}\\&=(mK_{n-1}+K_{n-2})S_{n}+(mK_{n-2}+K_{n-3})&&{\text{(regrouping)}}\\&=K_{n}S_{m}+K_{n-1}&&{\text{(recurrence on }}K_{n}).\end{aligned}}

End of the proof.

One has also ^{[citation needed]}

K_{n}={\frac {S_{m}^{n+1}-(m-S_{m})^{n+1}}{\sqrt {m^{2}+4}}}.

The odd powers of a metallic mean are themselves metallic means. More precisely, if $n$ is an odd natural number, then $S_{m}^{n}=S_{M_{n}},$ where $M_{n}$ is defined by the recurrence relation $M_{n}=mM_{n-1}+M_{n-2}$ and the initial conditions $M_{0}=2$ and $M_{1}=m.$

Proof: Let $a=S_{m}$ and $b=-1/S_{m}.$ The definition of metallic means implies that $a+b=m$ and $ab=-1.$ Let $M_{n}=a^{n}+b^{n}.$ Since $a^{n}b^{n}=(ab)^{n}=-1$ if $n$ is odd, the power $a^{n}$ is a root of $x^{2}-M_{n}-1=0.$ So, it remains to prove that $M_{n}$ is an integer that satisfies the given recurrence relation. This results from the identity

{\begin{aligned}a^{n}+b^{n}&=(a+b)(a^{n-1}+b^{n-1})-ab(a^{n-2}+a^{n-2})\\&=m(a^{n-1}+b^{n-1})+(a^{n-2}+a^{n-2}).\end{aligned}}

This completes the proof, given that the initial values are easy to verify.

In particular, one has

{\begin{aligned}S_{m}^{3}&=S_{m^{3}+3m}\\S_{m}^{5}&=S_{m^{5}+5m^{3}+5m}\\S_{m}^{7}&=S_{m^{7}+7m^{5}+14m^{3}+7m}\\S_{m}^{9}&=S_{m^{9}+9m^{7}+27m^{5}+30m^{3}+9m}\\S_{m}^{11}&=S_{m^{11}+11m^{9}+44m^{7}+77m^{5}+55m^{3}+11m}\end{aligned}}

and, in general,^{[citation needed]}

S_{m}^{2n+1}=S_{M},

where

M=\sum _{k=0}^{n}{{2n+1} \over {2k+1}}{{n+k} \choose {2k}}m^{2k+1}.

For even powers, things are more complicated. If $n$ is a positive even integer then^{[citation needed]}

{S_{m}^{n}-\left\lfloor S_{m}^{n}\right\rfloor }=1-S_{m}^{-n}.

Additionally,^{[citation needed]}

{1 \over {S_{m}^{4}-\left\lfloor S_{m}^{4}\right\rfloor }}+\left\lfloor S_{m}^{4}-1\right\rfloor =S_{\left(m^{4}+4m^{2}+1\right)}

{1 \over {S_{m}^{6}-\left\lfloor S_{m}^{6}\right\rfloor }}+\left\lfloor S_{m}^{6}-1\right\rfloor =S_{\left(m^{6}+6m^{4}+9m^{2}+1\right)}.

For the square of a metallic ratio we have: $S_{m}^{2}=[m{\sqrt {m^{2}+4}}+(m+2)]/2=(p+{\sqrt {p^{2}+4}})/2$

where $p=m{\sqrt {m^{2}+4}}$ lies strictly between $m^{2}+1$ and $m^{2}+2$ . Therefore

$S_{m^{2}+1}<S_{m}^{2}<S_{m^{2}+2}$

Generalization

One may define the metallic mean $S_{-n}$ of a negative integer $- n$ as the positive solution of the equation $x^{2}-(-n)x-1.$ The metallic mean of $- n$ is the multiplicative inverse of the metallic mean of $n$ :

S_{-n}={\frac {1}{S_{n}}}.

Another generalization consists of changing the defining equation from $x^{2}-nx-1=0$ to $x^{2}-nx-c=0$ . If

R={\frac {n\pm {\sqrt {n^{2}+4c}}}{2}},

is any root of the equation, one has

R-n={\frac {c}{R}}.

The silver mean of m is also given by the integral^[4]

S_{m}=\int _{0}^{m}{\left({x \over {2{\sqrt {x^{2}+4}}}}+{{m+2} \over {2m}}\right)}\,dx.

Another form of the metallic mean is^[4]

{\frac {n+{\sqrt {n^{2}+4}}}{2}}=e^{\operatorname {arsinh(n/2)} }.

Relation to half-angle cotangent

A tangent half-angle formula gives $\cot \theta ={\frac {\cot ^{2}{\frac {\theta }{2}}-1}{2\cot {\frac {\theta }{2}}}}$ which can be rewritten as $\cot ^{2}{\frac {\theta }{2}}-(2\cot \theta )\cot {\frac {\theta }{2}}-1=0\,.$ That is, for the positive value of ${\textstyle \cot {\frac {\theta }{2}}}$ , the metallic mean $S_{2\cot \theta }=\cot {\frac {\theta }{2}}\,,$ which is especially meaningful when ${\textstyle 2\cot \theta }$ is a positive integer, as it is with some Pythagorean triangles.

Relation to Pythagorean triples

Metallic Ratios in Primitive Pythagorean Triangles

For a primitive Pythagorean triple, $a 2 + b 2 = c 2$ , with positive integers $a < b < c$ that are relatively prime, if the difference between the hypotenuse $c$ and longer leg $b$ is 1, 2 or 8 then the Pythagorean triangle exhibits a metallic mean. Specifically, the cotangent of one quarter of the smaller acute angle of the Pythagorean triangle is a metallic mean.^[5]

More precisely, for a primitive Pythagorean triple $(a, b, c)$ with $a < b < c$ , the smaller acute angle $α$ satisfies $\tan {\frac {\alpha }{2}}={\frac {c-b}{a}}\,.$ When $c - b \in {1, 2, 8}$ , we will always get that $n=2\cot {\frac {\alpha }{2}}={\frac {2a}{c-b}}$ is an integer and that $\cot {\frac {\alpha }{4}}=S_{n}\,,$ the $n$ -th metallic mean.

The reverse direction also works. For $n \geq 5$ , the primitive Pythagorean triple that gives the $n$ -th metallic mean is given by $(n, n 2 /4 - 1, n 2 /4 + 1)$ if $n$ is a multiple of 4, is given by $(n /2, (n 2 - 4)/8, (n 2 + 4)/8)$ if $n$ is even but not a multiple of 4, and is given by $(4 n, n 2 - 4, n 2 + 4)$ if $n$ is odd. For example, the primitive Pythagorean triple $(20, 21, 29)$ gives the 5th metallic mean; $(3, 4, 5)$ gives the 6th metallic mean; $(28, 45, 53)$ gives the 7th metallic mean; $(8, 15, 17)$ gives the 8th metallic mean; and so on.

Numerical values

First metallic means^[6]^[7]
$n$	Ratio	Value	Name
$n$ $n$	${\frac {n+{\sqrt {4+n^{2}}}}{2}}$
0	${\frac {0+{\sqrt {4}}}{2}}=1$	1
1	${\frac {1+{\sqrt {5}}}{2}}$	1.618033988...^[8]	Golden
2	${\frac {2+{\sqrt {8}}}{2}}=1+{\sqrt {2}}$	2.414213562...^[9]	Silver
3	${\frac {3+{\sqrt {13}}}{2}}$	3.302775637...^[10]	Bronze^[11]
4	${\frac {4+{\sqrt {20}}}{2}}=2+{\sqrt {5}}$	4.236067977...^[12]	Copper^[11]^[a]
5	${\frac {5+{\sqrt {29}}}{2}}$	5.192582403...^[13]	Nickel^[11]^[a]
6	${\frac {6+{\sqrt {40}}}{2}}=3+{\sqrt {10}}$	6.162277660...^[14]
7	${\frac {7+{\sqrt {53}}}{2}}$	7.140054944...^[15]
8	${\frac {8+{\sqrt {68}}}{2}}=4+{\sqrt {17}}$	8.123105625...^[16]
9	${\frac {9+{\sqrt {85}}}{2}}$	9.109772228...^[17]
10	${\frac {10+{\sqrt {104}}}{2}}=5+{\sqrt {26}}$	10.099019513...^[18]

👽🔭PhxMarkER🌌🔬🐁🕯️⚡🗝️

Monday, October 6, 2025

Solving Unsolved Problems in Physics Using the Super Golden TOE

Solving Unsolved Problems in Physics Using the Super Golden TOE

Authors

Quantum Gravity Problems

Cosmology and General Relativity Problems

High-Energy/Particle Physics Problems

Condensed Matter Physics Problems

Astronomy and Astrophysics Problems

Nuclear Physics Problems

Biophysics Problems

Foundations of Physics Problems

General Physics Problems

🚂🎢NCSWIC: Unification! Video 1! - 19th Nervous Breakdown: Here's It Comes!!!🚂🎢

Resolving Cosmological Tensions with Moduli Fields in the Super Golden TOE: A Golden Ratio Hierarchy Approach

Resolving Cosmological Tensions with Moduli Fields in the Super Golden TOE: A Golden Ratio Hierarchy Approach

bAbstract

1. Introduction

2. Theoretical Framework

2.1 Moduli in String Theory and the TOE

2.2 Equation of Motion

3. Simulations and Results

4. Resolving Other Tensions

5. Conclusion

Analysis of the Early Long String, Chain, or Thread of Galaxies

Sunday, October 5, 2025

Metallic mean

Metallic mean

Geometry

Powers

Generalization

Relation to half-angle cotangent

Relation to Pythagorean triples

Numerical values

See also