Rewritten: $$\mu m_e={2\eta\over R}m_{\ell}$$

The proton to electron mass ratio: $$\mu={2\eta\over R}{m_{\ell}\over m_e}$$

What is the mass of the electron, the first generation lepton? $$m_e={2R_{\infty}h\over c\alpha^2}[1]$$

[1]https://en.wikipedia.org/wiki/Electron_rest_mass The Rydberg constant is empirical, thus this equation is not analytical, however, we shall proceed:

∴, $$\mu={m_p\over m_e}= {\alpha^2\over \pi r_pR_{\infty}}=1836.15267\;\;\leftarrow\;significant!!!$$

$\alpha$ is the fine-structure constant

$r_p$ is the proton radius (use 2010 & 2013 muonic hydrogen radius and Haramein's equation)

$R_{\infty}$ is the Rydberg Constant.

Google Calculator link for $\mu$:

CALC LINK

Alternate form (definition, trivial): $$\mu={m_p\over m_e}= {m_pc\alpha^2\over{2R_{\infty}h}}=1836.15267$$

Google Calculator Link Alternate Form

Compare to ฮผ = mp/me = 1836.15267245(75).[1]

What is the Planck mass to electron mass ratio? $$\Phi={m_{\ell}\over m_e}$$

Using Haramein's proton solution, and equating it to $r_em_e$:

$$m_pr_p=4\ell m_{\ell}=r_em_e$$

This is the torque-spin balance proposal of Lyz Starwalker.

$$r_em_e=4\ell m_{\ell}$$

$${m_{\ell}\over m_e}={r_e\over 4\ell}$$

$${m_{\ell}\over m_e}={{\alpha^2\over 4\pi\ell R_{\infty}}}=2.3893048e+22$$

Google Calculator Link for Planck Mass divided by Electron Mass

PlanckMass/ElectronMass <~~~ Google Calculator

http://m.primber.com/23893048.html

I think Sadhguru can tell us what level this is away from our senses... ...the lepton???

Using Haramein's equation for the proton radius and the 2010 & 2013 muonic hydrogen measurement of the proton radius, we have a simple equation that shows the correct ratio of the proton to electron mass ratio. The only issue is that still the electron has no analytical solution to its mass. Since the electron is not an actual particle, it is possible that it does not have a solution like the proton does, however, we'll keep looking. However, this equation for $\mu$, the proton-electron mass ratio is very good for now!

Some Links to proton/electron mass ratio:

Compare to http://www.ptep-online.com/index_files/2015/PP-40-04.PDF <--- $\mu$ equations 2015

Addendum for future investigation (torque balance): $$m_pr_p=r_em_e\;where\;r_e={\alpha^2\over\pi R_{\infty}}$$

More Later,

The proton to electron mass ratio: $$\mu={2\eta\over R}{m_{\ell}\over m_e}$$

What is the mass of the electron, the first generation lepton? $$m_e={2R_{\infty}h\over c\alpha^2}[1]$$

[1]https://en.wikipedia.org/wiki/Electron_rest_mass The Rydberg constant is empirical, thus this equation is not analytical, however, we shall proceed:

∴, $$\mu={m_p\over m_e}= {\alpha^2\over \pi r_pR_{\infty}}=1836.15267\;\;\leftarrow\;significant!!!$$

$\alpha$ is the fine-structure constant

$r_p$ is the proton radius (use 2010 & 2013 muonic hydrogen radius and Haramein's equation)

$R_{\infty}$ is the Rydberg Constant.

Google Calculator link for $\mu$:

CALC LINK

Alternate form (definition, trivial): $$\mu={m_p\over m_e}= {m_pc\alpha^2\over{2R_{\infty}h}}=1836.15267$$

Google Calculator Link Alternate Form

Compare to ฮผ = mp/me = 1836.15267245(75).[1]

What is the Planck mass to electron mass ratio? $$\Phi={m_{\ell}\over m_e}$$

Using Haramein's proton solution, and equating it to $r_em_e$:

$$m_pr_p=4\ell m_{\ell}=r_em_e$$

This is the torque-spin balance proposal of Lyz Starwalker.

$$r_em_e=4\ell m_{\ell}$$

$${m_{\ell}\over m_e}={r_e\over 4\ell}$$

$${m_{\ell}\over m_e}={{\alpha^2\over 4\pi\ell R_{\infty}}}=2.3893048e+22$$

Google Calculator Link for Planck Mass divided by Electron Mass

PlanckMass/ElectronMass <~~~ Google Calculator

http://m.primber.com/23893048.html

I think Sadhguru can tell us what level this is away from our senses... ...the lepton???

Using Haramein's equation for the proton radius and the 2010 & 2013 muonic hydrogen measurement of the proton radius, we have a simple equation that shows the correct ratio of the proton to electron mass ratio. The only issue is that still the electron has no analytical solution to its mass. Since the electron is not an actual particle, it is possible that it does not have a solution like the proton does, however, we'll keep looking. However, this equation for $\mu$, the proton-electron mass ratio is very good for now!

Some Links to proton/electron mass ratio:

Compare to http://www.ptep-online.com/index_files/2015/PP-40-04.PDF <--- $\mu$ equations 2015

Addendum for future investigation (torque balance): $$m_pr_p=r_em_e\;where\;r_e={\alpha^2\over\pi R_{\infty}}$$

More Later,

**The Surfer, OM-IV**
This is fun-fundamental work. Anyone else derive this equation?

ReplyDeletea couple minor updates, clarifications, plus a future direction concerning the electron-proton torque balance. It is wholly about balance...

ReplyDeleteupdated to include Planck Mass to Electron mass ratio

ReplyDeleteit is incredible the accuracy of Haramein's proton radius solution and the theory behind its derivation it provides.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteanother significant scientific fact here, besides the few obvious ones, is torque balance concept. This proton-electron balance is their dance MpRp=ReMe <-- this product and it's derivation have GREAT significance as it gives a little more insight into the behavior of the atom. In the background of unified physics, it is actually quite easy to discuss what is happening with the proton and electrons and all once one really knows what is happening, and I'm not quite there yet, lol.

ReplyDeleteMpRp=ReMe is known as the "Rohrbaugh Ratio" and is the 1st step in unifying how we look at the atom.

ReplyDeletethere will be a minor update soon - there a minor typo - inversion in an equation or two... this math is simple enough, so it'll be corrected in a bit...

ReplyDeleteSorry for the error, it is correct now... updated Planck Mass to Electron Mass ratio and added the details from Lyz Starwalker's analysis.

ReplyDeleteQED.

ReplyDeletejust made a correction to some math due to not using enough digits (and the proper equation for the radius of the proton, lol). Still, everything adds up... -mr

ReplyDelete